Laplace's Algorithm
- Define function
- Get the values of Boundary Conditions
- Get values of aerr and maxitr
- loop
- i=2,j=2
- n = (xn – x0)/h + 1
- is err>maxerr
- print results
- Stop
- The accuracy of calculations depends on the mesh-size, i.e., smaller the h,
the better the accuracy. But if h is too small, it may increase rounding-off
errors and also increases the labor of computation.